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1Z0-106 Valid Exam Objectives, 1Z0-106 New Braindumps Ebook

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Oracle 1Z0-106 Certification Exam is an industry-recognized certification exam designed for professionals who want to validate their expertise in Oracle Linux 8 Advanced System Administration. 1Z0-106 exam is designed to test the candidates' advanced skills in system administration, including networking, security, storage management, and high availability. Oracle Linux 8 Advanced System Administration certification is essential for professionals looking to advance their careers in Oracle Linux 8 System Administration, and it provides a solid foundation for professionals who want to specialize in advanced system administration tasks.

Oracle 1Z0-106 Exam is designed for individuals who want to validate their expertise in Oracle Linux 8 Advanced System Administration. 1Z0-106 exam is intended for professionals who have experience in installing and configuring Oracle Linux 8 systems and managing them in an enterprise environment. Individuals who pass 1Z0-106 exam will earn the Oracle Certified Professional (OCP) certification, which is recognized globally as a hallmark of expertise and knowledge in the field of IT.

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Oracle 1Z0-106 (Oracle Linux 8 Advanced System Administration) exam is a certification exam designed to test the knowledge and skills of professionals who are responsible for administering and managing Oracle Linux 8 systems in an enterprise environment. 1Z0-106 Exam focuses on advanced system administration topics, such as configuring network services, managing storage, and troubleshooting system issues.

Oracle Linux 8 Advanced System Administration Sample Questions (Q14-Q19):

NEW QUESTION # 14
Examine these Kubernetes components:

Which option correctly matches the components with their description?

A. 1-b, 2-a, 3-e, 4-c, 5-f, 6-d
B. 1-d, 2-f, 3-c, 4-e, 5-a, 6-b
C. 1-d, 2-f, 3-e, 4-a, 5-c, 6-b
D. 1-c, 2-f, 3-d, 4-b, 5-e, 6-a
E. 1-a, 2-d, 3-b, 4-c, 5-e, 6-f

Answer: B

Explanation:
Explanation of Answer E:This option correctly matches the Kubernetes components with their descriptions:
* Kubectl- d. Command-line interface used to control Kubernetes
* Etcd- f. Stores configuration data relating to the cluster
* Kubelet- c. Agent that allows nodes to communicate with the API
* Kube-proxy- e. Performs networking functions and routes network traffic
* Kube-apiserver- a. Processes and validates requests and performs operations
* Kube-scheduler- b. Determines where containers should run based on resource availability

NEW QUESTION # 15
You must add an additional swap device and you add this entry to /etc/fstab:
/.swapfile none swap defaults 0 0
Examine these commands and output:
# dd if=/dev/zero of=/.swapfile bs=1024 count=1048576
1048576+0 records in
1048576+0 records out
1073741824 bytes (1.1 GB, 1.0 GiB) copied, 4.32499 s, 248 MB/s
# swapon -a
swapon: /.swapfile: insecure permissions 0644, 0600 suggested.
swapon: /.swapfile: read swap header failed
Which two actions must you perform to add this swap device?

A. Change defaults to user in the /etc/fstab entry.
B. Execute swapon -all.
C. Assign a label to the .swapfile file by using the swaplabel command.
D. Execute swapon -L swapfile /.swapfile after adding a label.
E. Initialize the .swapfile file by using the mkswap command.
F. Use a physical disk partition type of 82 (Linux swap).

Answer: C,E

Explanation:
To use a file as swap space, it must first be initialized with themkswapcommand. Theddcommand creates an empty file, butmkswapformats this file to be used as swap space. This command writes the necessary swap header to the file, making it recognizable by the system as a valid swap area.
Explanation of Answer D:After initializing the swap file withmkswap, you can optionally assign a label to the swap file using theswaplabelcommand. This is not strictly required, but it can be useful for identifying swap files, especially if you are using multiple swap devices.

NEW QUESTION # 16
Which three statements are true about the journalctl command?

A. journalctl -bl -p err fails if journal persistence is not configured.
B. journalctl -k shows kernel logs since the last boot.
C. journalctl -p notice..warning shows all messages from notice to warning log level since the last boot.
D. journalctl -p err shows only error log level.
E. journalctl -p 6 shows all info log level messages and above.

Answer: B,D,E

Explanation:
Option B: journalctl -p err shows only error log level.
* Explanation:
* The -p or --priority option in journalctl filters messages by their priority level.
* When specifying asingle priority level, journalctl shows messagesonlyat that level.
* The priority levels, as per syslog standards, are:
* 0: emerg
* 1: alert
* 2: crit
* 3: err
* 4: warning
* 5: notice
* 6: info
* 7: debug
* Therefore, journalctl -p err displays messages with priorityerr (3)only.
* Oracle Linux Reference:
* OracleLinux 8: Managing Log Files- Section onFiltering Output withjournalctl:
"Use the -p option to display messages from the journal that have a specific priority level."
* Example:
# journalctl -p err
Option D: journalctl -k shows kernel logs since the last boot.
* Explanation:
* The -k or --dmesg option filters messages from the kernel, equivalent to the output of the dmesg command.
* This option implies -b, which limits the output to messages from the current boot.
* Therefore, journalctl -k displays kernel messages since the last boot.
* Oracle Linux Reference:
* OracleLinux 8: Managing Log Files- Section onViewing Kernel Messages:
"Use the journalctl -k command to display kernel messages since the last system boot."
* Example:
# journalctl -k
Option E: journalctl -p 6 shows all info log level messages and above.
* Explanation:
* When specifying a single numeric priority, journalctl displays messages withthat priority level and higher priority levels(i.e., lower severity).
* Priority levels are ordered from 0 (highest severity) to 7 (lowest severity).
* Therefore, journalctl -p 6 shows messages with priorities:
* 0 (emerg)
* 1 (alert)
* 2 (crit)
* 3 (err)
* 4 (warning)
* 5 (notice)
* 6 (info)
* This includesinfo level messages (6)and all higher priority messages.
* Oracle Linux Reference:
* OracleLinux 8: Managing Log Files- Section onFiltering Output with journalctl:
"When you specify a single priority level, journalctl shows messages at that level and higher severity."
* Example:
# journalctl -p 6
Why Other Options Are Not Correct:
* Option A:journalctl -bl -p err fails if journal persistence is not configured.
* Explanation:
* The -b option displays messages from the current boot. This works even if journal persistence isnotconfigured because the logs from the current boot are stored in volatile memory (/run/log/journal).
* Therefore, the command doesnot failif journal persistence is not configured.
* Oracle Linux Reference:
* OracleLinux 8: Managing Log Files- Section onJournal Volatility:
"By default, the journal stores logs in volatile memory and does not persist logs across reboots unless persistent storage is configured."
* Option C:journalctl -p notice..warning shows all messages from notice to warning log level since the last boot.
* Explanation:
* The -p option allows specifying arangeof priorities. However, the correct order for the range should be from thehigher priority (lower number)to thelower priority (higher number).
* Also, the priorities should be specified in the correct sequence, and ranges are inclusive.
* Moreover, journalctl by default shows messages from all boots unless limited by the -b option.
* Therefore, without -b, it does not limit messages to "since the last boot," making the statement incorrect.
* Correct Command:
* To display messages fromwarning (4)tonotice (5), the command should be:
# journalctl -p warning..notice -b
* But even then, the priorities need to be specified correctly, and the command in Option C is incorrect.
Conclusion:
OptionsB,D, andEare correct because they accurately describe the behavior of the journalctl command in filtering and displaying log messages based on priority levels and sources.

NEW QUESTION # 17
Which two statements are true about fdisk?

A. It can partition disks larger than 2 TB by using a GPT partition table.
B. It cannot partition disks larger than 2 TB by using a GPT partition table.
C. fdisk -l displays disk size information for all disks.
D. It understands GPT, MBR, and HFS partition tables.
E. It can divide logical devices into one or more block disks called partitions.

Answer: A,C

NEW QUESTION # 18
Examine these commands executed by root:
# mkdir -p /jail /jail/bin /jail/lib64
# cp $(which bash) /jail/bin/
# ldd $(which bash)
linux-vdso.so.1 (0x00007ffd574f5000)
libtinfo.so.6 => /lib64/libtinfo.so.6 (0x00007fb458c2c000)
libdl.so.2 => /lib64/libdl.so.2 (0x00007fb458a28000)
libc.so.6 => /lib64/libc.so.6 (0x00007fb458666000)
/lib64/ld-linux-x86-64.so.2 (0x00007fb459177000)
# cp /lib64/libtinfo.so.6 /jail/lib64/
# cp /lib64/libdl.so.2 /jail/lib64/
# cp /lib64/libc.so.6 /jail/lib64/
# cp /lib64/ld-linux-x86-64.so.2 /jail/lib64/
# chroot /jail
What is the output from the cd, pwd, and ls commands?

A. bash-4.4# cd
bash: cd: /root: No such file or directory
bash-4.4# pwd
/root
bash-4.4# ls
bash: ls: command not found
B. bash-4.4# cd
bash: cd: command not found
bash-4.4# pwd
bash: pwd: command not found
bash-4.4# ls
bash: ls: command not found
C. bash-4.4# cd
bash: cd: /root: Unable to access chrooted file or directory /root
bash-4.4# pwd
/
bash-4.4# ls
bin lib64
D. bash-4.4# cd
bash: cd: /root: No such file or directory
bash-4.4# pwd
/
bash-4.4# ls
bin lib64

Answer: D

Explanation:
Explanation of Answer A:When thechrootcommand is executed with/jail, the environment is changed to use
/jailas its new root directory. Inside this environment, only the directories and files copied into/jailare accessible. Since/jaildoes not contain a/rootdirectory, the commandcd(which defaults to changing to the user's home directory) will fail, displayingNo such file or directory. Thepwdcommand shows the root of the chroot environment (/), andlsdisplays the contents of/jail, which includesbinandlib64.

NEW QUESTION # 19
......

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